- Write a C program to print fibonacci series till Nth term.

Fibonacci series are the numbers in the following integer sequence

0, 1, 1, 2, 3, 5, 8, 13, 21, 34, 55, 89 ….

the first two numbers in the Fibonacci sequence are 0 and 1, and each subsequent term is the sum of the previous two terms. In mathematical terms, the Nth term of Fibonacci numbers is defined by the recurrence relation:

fibonacci(N) = Nth term in fibonacci series

fibonacci(N) = fibonacci(N – 1) + fibonacci(N – 2);

whereas, fibonacci(0) = 0 and fibonacci(1) = 1

**Interesting facts**

- If you take any two successive (one after the other) Fibonacci Numbers, their ratio is very close to the Golden Ratio which is approximately 1.618034.
- The bigger the pair of Fibonacci Numbers, the closer the approximation.

### C program to print fibonacci series till Nth term

In this program we first take number of terms in fibonacci series as input from user. Then starting with 0 and 1 as first two terms of the fibonacci series we generate and print consecutive fibonacci numbers by adding last two terms using a for loop.

/* * C Program to print fibonacci series */ #include <stdio.h> #include <conio.h> int main(){ int terms, lastNumber=1,secondLast=0,currentNumber=0,counter; printf("Enter number of terms in Fibonacci series: "); scanf("%d", &terms); /* * Nth term = (N-1)th therm + (N-2)th term; */ for(counter = 0; counter < terms; counter++){ if(counter < 2){ currentNumber = counter; } else { currentNumber = lastNumber + secondLast; secondLast = lastNumber; lastNumber = currentNumber; } printf("%d ", currentNumber); } getch(); return 0; }

**Program Output**

Enter number of terms in Fibonacci series: 8 0 1 1 2 3 5 8 13

### C Program to generate fibonacci series till Nth term and store it in array

In this program we use an array to store fibonacci series generated till now. Every fibonacci number is equal to the sum of values in last two indexes of fibonacci array.

fibonacciArray[N] = fibonacciArray[N - 1] + fibonacciArray[N - 2];

/* * C Program to print fibonacci series using array */ #include <stdio.h> #include <conio.h> int main(){ int terms, fibonacciArray[100] = {0}, counter; printf("Enter number of terms in Fibonacci series: "); scanf("%d", &terms); for(counter = 0; counter < terms; counter++){ if(counter < 2){ fibonacciArray[counter] = counter; } else { fibonacciArray[counter] = fibonacciArray[counter - 1] + fibonacciArray[counter - 2]; } printf("%d ", fibonacciArray[counter]); } getch(); return 0; }

**Program Output**

Enter number of terms in Fibonacci series: 10 0 1 1 2 3 5 8 13 21 34

### C program to print fibonacci series using recursion

This program uses recursion to calculate Nth fibonacci number, fibonacci(N) returns Nth fibonacci number by recursively calling fibonacci(N – 1) and fibonacci(N – 2). fibonacci(N) function does lots of repeated work by recalculating lower terns again and again.

For example:

fibonacci(5) = fibonacci(4) + fibonacci(3);

It calculates value of 3rd and 4th term of fibonacci series to get 5th term.

fibonacci(6) = fibonacci(5) + fibonacci(4);

Now, while calculating 6th term, it again calculate 5th and 4th term which we already calculated while generating 5th term. We can solve this problem of recalculating already calculated terms by storing all previous terms in an array. This approach is called recursion with memorization(Dynamic Programming).

/* * C Program to print fibonacci series using recursion */ #include <stdio.h> #include <conio.h> int fibonacci(int term); int main(){ int terms, counter; printf("Enter number of terms in Fibonacci series: "); scanf("%d", &terms); /* * Nth term = (N-1)th therm + (N-2)th term; */ for(counter = 0; counter < terms; counter++){ printf("%d ", fibonacci(counter)); } getch(); return 0; } /* * Funtion to calculate Nth Fibonacci number * fibonacci(N) = fibonacci(N - 1) + fibonacci(N - 2); */ int fibonacci(int term){ /* Exit condition of recursion*/ if(term < 2) return term; return fibonacci(term -1) + fibonacci(term - 2); }

**Program Output**

Enter number of terms in Fibonacci series: 9 0 1 1 2 3 5 8 13 21